Physics High School

## Answers

**Answer 1**

**Earth's** inner movements resemble dynamos and produce the magnetosphere. The **magnetosphere** of Earth is a dynamic, networked system that reacts to solar, planetary, and interstellar circ*mstances.

The area surrounding a **planet** where the magnetic field of the planet is dominant is called a magnetosphere. All of the rocky planets in our solar system have magnetospheres, but** Earth's** is the strongest. The enormous, comet-shaped bubble that makes up Earth's magnetosphere has been essential to the planet's capacity to support life. This magnetic environment has protected life on Earth from its inception and continues to do so. The magnetosphere protects our planet from **solar** and cosmic ray radiation as well as the solar wind's steady stream of charged particles that stream off the sun, which may erode the **atmosphere**.

Due to the convective motion of charged,

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## Related Questions

A 1 m spring requires 10 J to stretch the spring to 1. 1 m. How much work would it take to stretch the spring from 1 m to 1. 2 m

### Answers

It would take 8 J of work to **stretch** the spring from 1 m to 1.2 m.

The work required to **stretch** a spring is given by the formula:

[tex]W = (1/2)kx^2,[/tex] where W is the **work** **done**, k is the spring constant, and x is the **distance** the spring is stretched or compressed.

Given that the **spring** requires 10 J of work to stretch from 1 m to 1.1 m, we can calculate the spring constant as follows:

[tex]10 J = (1/2)k(0.1 m)^2[/tex]

[tex]k = 200 J/m[/tex]

Using this spring constant, we can **calculate** the **work** required to stretch the spring from 1 m to 1.2 m:

[tex]W = (1/2)(200 J/m)(0.2 m)^2[/tex]

[tex]W = 8 J[/tex]

Therefore, it would take 8 J of work to stretch the spring from 1 m to 1.2 m.

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the motorcycle is traveling at a constant speed of 60 km>h. determine the magnitude of its acceleration when it is at point a.

### Answers

The magnitude of its **acceleration** when it is at point a. is 0.763 [tex]m/s^2[/tex]

**Acceleration** is the rate at which the speed and direction of a moving object change over time.Something is said to be accelerating when it starts to move faster or slower.Motion on a circle **accelerates** even while the speed is constant because the direction is always changing.These collisions lead to an acceleration of all other motion types.Another vector quantity is velocity. The change in **velocity** vector over a time interval divided by the time interval is the definition of **acceleration**.

[tex]y=\sqrt2 x^{\frac{1}{2} }[/tex]

[tex]\frac{dy}{dx} =\frac{1}{2} \sqrt2x^{\frac{-1}{2} }[/tex]

[tex]\frac{d^2y}{dx^2} =\frac{-1}{4} \sqrt2x^{\frac{-3}{2} }[/tex]

[tex]p=\frac{[1+\frac{dy}{dx}^2]^{\frac{3}{2} } }{\frac{d^2y}{dx^2}} =\frac{[1+\frac{1}{2} \sqrt2x^{\frac{-1}{2} }]^{\frac{3}{2} } }{\frac{-1}{4} \sqrt2x^{\frac{-3}{2} }} \\:[/tex] at x= 25m

p=364.21 m

acceleration: the **speed** of motorcycle at a is

v = [tex](60) \frac{km}{h}(\frac{1000 m}{1Km})(\frac{1h}{3600s})[/tex]= 16.67 m/s

[tex]a_n=\frac{v^2}{p}=\frac{16.67^2}{364.21}=0.7627 \: m/s^2[/tex]

since the motorcycle travels with the constant speed a=0 the magnitude of acceleration of motorcycle at a is

a=[tex]\sqrt{a_r^2+a_n^2}=\sqrt{0^2+0.7627^2}=0.763\: m/s^2[/tex]

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a student pushes against a wall until they are exhausted!!! (and obviously the wall doesn't move) has the student done any work on the wall?

### Answers

No, the student has not done any **work **on the wall. Work is defined by physics as the** transfer of energy **from one object to another.

In this case, the student is **exerting a force** on the wall, but since the wall is not moving, no energy is being transferred and thus no work has been done.

Work is a fundamental **concept in physics**, and it can help us better understand how objects interact with each other and the environment around them. In a general sense, work is defined as the transfer of energy from one object to another, usually through the application of a force. This means that when a force is applied to an object, work is done on it and the object moves in the direction of the applied force.

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why is the current across a drain resistor the same as the current across drain to source in a mosfet

### Answers

The current across a drain** resistor** is the same as the current across the drain to source in a MOSFET because the MOSFET behaves as a voltage-controlled resistor.

What is resistor ?

A resistor is an **electrical component** that is used to reduce the flow of current in an electrical circuit. It works by creating electrical resistance, which is measured in ohms. This resistance opposes the flow of current, allowing engineers to control the voltage and current levels in a circuit. Resistors are used in many different types of applications, from controlling the speed of motors to regulating the flow of current in digital circuits.

The resistance of the **MOSFET **channel is controlled by the voltage applied to the gate. If the gate voltage is increased, the resistance of the channel decreases, allowing more current to flow from the drain to the source. Since the drain resistor is in series with the MOSFET channel, the same current must also flow through the resistor.

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a 7.2 nc point charge and a - 2.7 nc point charge are 3.0 cm apart. what is the electric field strength at the midpoint between the two charges?

### Answers

The **electric field **strength at the midpoint between two charges is [tex]10^3[/tex]N/C.

The electric field strength at a point in space is defined as the **force **per unit charge at that point. The electric field strength due to a point charge can be calculated using Coulomb's law: E = kQ / r^2, where k is the **Coulomb **constant, Q is the charge of the point charge, and r is the distance from the point charge to the point where the field strength is being calculated.

In this case, the electric field strength at the midpoint between the two charges can be calculated by finding the vector sum of the electric field strengths due to each of the two charges. The midpoint is **equidistant **from both charges, so the electric field strengths due to each charge will have equal magnitude and point in opposite directions.

Thus, the vector sum of the two electric field **strengths **will be equal to their difference, or E = kQ / [tex]r^2[/tex], where Q is the net charge (7.2 nC - (-2.7 nC) = 9.9 nC) and r is the distance from each charge to the midpoint (3.0 cm). Plugging in the numbers, the electric field strength is

E = [tex](9 * 10^9 N m^2/C^2) * (9.9 * 10^{-9} C) / (3 * 10^{-2} m)^2 = 10^3 N/C[/tex].

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a student has built a 10-cm-long pinhole camera for a science-fair project. she wants to photograph her friend, who is 180 cm tall, and have the image on the film be 5 cm high. how far should the front of the camera be from her friend

### Answers

The **distance** between both the student's **friend** and **camera** is **d = 360 cm **or **3.6 m**.

What is the structure of light?

Light not only moves in **waves**; it also moves with a flow of small particles. Scientists call these tiny particles of light as **photons**. The packets contain the energy which makes up the energy of the light. The scientists measure something called the **relative energy **for different types of light.

The light traveling in any one **direction** in a straight line is called a r**ay of light**. Meanwhile, a group of light rays given out from a source is called a **beam of light**.

In this case, camera’s **height** was 10 cm.

The height of student's friend was 180 cm.

That picture on camera has a** length** of 5 cm.

Now, let d represent the space among both the friend and device's face. Its** identical triangles** as in figure attached show how the lengths were connected.

So, to find out the distance, we can use the following** equation**:

5 cm / 10 cm = 180 cm / d

d = 10 cm * 180 cm / 5 cm

d = 360 cm

d = **3.6 m**

Hence, the** distance** among both the friend and device's face is **360 cm** or 3.6 m.

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describe the circuitry of three strings of patio lights plugged into the same extension cord. one whole string does not light, but all the bulbs in the other two strings do.

### Answers

The **connection **of three strings of **patio lights**, One whole string does not light, but all **bulbs **in the other two strings do three strings are connected in series, while each string's** bulbs **are connected in **parallel**.

The **voltage **across each component in a **parallel connection **is equal to voltage throughout the network, despite each component being connected via a different path.

The three strings are connected in **series**, while each string's bulbs are connected in **parallel**. The remaining **strings of bulbs **will continue to glow even if one bulb in a string fails.

Therefore, three **strings **are **connected **in **series **while each string's bulbs are connected in **parallel**.

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a mass of 5 lb is acted upon by an upward force of 16 lb. the only additional force on the mass is the force of gravity. find the acceleration in ft/s2 . is this acceleration upward or downward?\

### Answers

**A mass** of 5 lb is acted upon by an upward force of 16 lb. the only **additional force** on the mass is the force of gravity. The acceleration is -29 ft/[tex]s^{2}[/tex], which is downward.

The net force on the 5 lb mass is equal to the difference between the upward force and the force of gravity. **The force of gravity **can be calculated as follows:

fgravity = m . g

where,

m = 5 lb (mass)

g = 32.2 ft/[tex]s^{2}[/tex] (acceleration due to gravity)

So,

fgravity = 5 lb * 32.2 ft/[tex]s^{2}[/tex] = 161 lb

The net force on the mass can then be calculated as follows:

fnet = fupward - fgravity = 16 lb - 161 lb = -145 lb

Since the net force is negative, it acts in the downward direction. To calculate** the acceleration**, we use Newton's second law of motion:

f = ma

where,

m = 5 lb (mass)

a = acceleration

Solving for acceleration, we get:

a = fnet / m = -145 lb / 5 lb = -29 ft/[tex]s^{2}[/tex]

So, the acceleration is -29 ft/[tex]s^{2}[/tex], which is downward.

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why is a battery used when we require more electricity

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A **battery **is used when we require more electricity because it can store and release **electrical **energy as needed.

Batteries consist of one or more cells, each of which contains two **electrodes **and an electrolyte that allows for the flow of charged particles between the electrodes. When a battery is connected to a device, the charged particles flow from the positively **charged **electrode to the negatively charged electrode, providing a flow of electricity.

The amount of electricity stored in a battery is limited, but it can be released as needed, even when the source of the electricity is not available. This makes batteries useful for supplying electrical energy in situations where there is a **temporary** increase in demand, such as when more devices are turned on or when the source of electrical energy is unavailable, such as during a power outage.

Additionally, batteries are **portable **and can be easily carried, making them useful for supplying electrical energy in remote locations where there is no access to the electrical grid.

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if the rock takes 0.34 s to cross the 2.2- m -high glass door, from what height above the top of the door was it dropped? express your answer to two significant figures and include the appropriate units.

### Answers

The **rock** was dropped from a height of 2.2 m above the top of the door.

What is **rock**?

Rock is a natural and solid material made up of minerals and other substances. It is typically found in **mountainous areas**, deserts, and other areas where the Earth's crust is exposed. It is composed of different minerals which give it its hardness and durability. Rock is used in numerous construction projects and other applications. It provides a strong foundation for structures and is used in construction, landscaping, and even in art.

The equation used to solve this problem is s = vt, where s is the distance, v is the velocity, and t is the time.

The velocity of the rock is found by **rearranging the equation** to v = s/t, so v = 2.2 m / 0.34 s = 6.47 m/s.

The initial height of the rock is found by rearranging the equation to s = vt to s = 6.47 m/s * 0.34 s = 2.2 m.

Therefore, the rock was dropped from a height of 2.2 m above the top of the door. Expressed to two significant figures, this is 2.2 m.

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imagine that the universe is a cubical box. if the universe initially contains equal amounts of all four elements, at all points, and the elements are then allowed to perform natural motions according to principles you discovered in (1) above, what will the final structure of the universe be?

### Answers

If the **universe **initially contains** equal amounts **of all four elements, and the elements are then allowed to **perform natural motions** according to the principles discovered above, the final structure of the universe will be determined by the relative strengths of the forces acting on each element.

The **stronger forces** will cause the elements to move in certain directions and create patterns in the universe. For example, the forces of gravity, **electrostatic forces**, and magnetic forces will cause the Earth and Water elements to form planets, while the Air and Fire elements will form galaxies and stars. The final structure of the universe will depend on the balance of these forces and the motion of the elements.

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a 10kg box has u of 0.4 with surface if the box accelerates at 1.08 m\s^2 what was the applied force

### Answers

**Answer:**

The distance from Jerusalem to Galilee is approximately 150 km depending on the route you take. You can get a bus from Jerusalem's central bus station to Tiberias, on the edge of the Sea of Galilee. The journey takes about 2-3 hours.Sep 4, 2019

moral lesson learnt from the sermon on the mount

### Answers

**Blessed are the merciful: for they shall obtain mercy** is the moral lesson learned from the sermon on the mount

**What is the Sermon on the Mount's main message?**

Christians learn the following crucial lessons from this sermon: The things we own here on Earth don't matter. Good people will discover meaningful spiritual "**treasures**" in Heaven. God will take care of people, so they shouldn't be concerned.

**In the Sermon on the Mount, what did Jesus say?**

1. And, seeing the crowds, he climbed a mountain: His disciples came to him after he was set.

2. And he spoke to them, saying

3. Because the kingdom of heaven is theirs, those who are poor in spirit are blessed.

4. Happy are the bereaved because they will find comfort.

**Who wrote the sermon on the Mount?**

**Scholars **put forth a number of arguments for the claim that Matthew is the author of the Sermon on the Mount, but only using **New Testament sources**.

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what would liekly happen if a hot saturated solution of a solid were filtered either by vacuum or gravity filtration

### Answers

If a hot saturated **solution **of a solid were **filtered **either by vacuum or gravity filtration, the solute begins to **precipitate**.

In the case of **vacuum filtering **with a Buchner funnel, a hot saturated solution would cool as it made contact with the funnel. The solution becomes less soluble at decreasing temperatures. Solute starts to precipitate as a result. The **cooling **process moves quite quickly.

The overall **yield **of the targeted **product **will suffer as a result. It is recommended against suction **filtration **of hot solutions that contain solvents with lower **boiling **points than water.

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(q1) two charged spheres are 10.68 cm apart. they are moved, and the force on each of them is found to have been tripled. how far apart are they now?

### Answers

The spheres are now 6.08 cm apart. The force between two **charged** spheres is proportional to the product of their charges and inversely proportional to the square of the** distance** between them.

This means that if the **force **is tripled, the distance between the spheres must have been reduced by a factor of the square root of 3. To find the new distance, we can use the formula:

d_new = d_old / √3

Where d_old is the **original distance** of 10.68 cm and d_new is the new distance. Plugging in the values, we get:

d_new = 10.68 cm / √3 = 6.08 cm

So, the spheres are now 6.08 cm apart.

In this case, F_old / F_new = 1/3, since the force has been tripled. Plugging in the original distance of 10.68 cm and the value for F_old / F_new, we can calculate the new distance. The final result shows that the** spheres **are now 6.08 cm apart.

This result shows how the force between **charged** spheres is directly influenced by the distance between them. Understanding this relationship is important in many fields, including physics, electrical engineering, and materials science.

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suppose an artificial satellite has been put into circular orbit about the earth, at a distance from the center of the earth equal to 1/4 the distance from the earth's center to the moon's center. in terms of the moon's period tm, what will be the period of the satellite?

### Answers

The formula [tex]Ts = (tm^2 / rm^3)^(1/2) * (rm / 4)^(3/2)[/tex] if an **artificial satellite **has been put into circular orbit about the** earth,** at a distance from the center of the earth equal to 1/4 the distance from the earth's center.

To find the period of the **satellite, **we can use Kepler's Third Law of Planetary Motion, which states that the square of the period of a planet or satellite is proportional to the cube of its average distance from the center of the planet or central body. **Mathematically,** this can be expressed as:

[tex]T^2 = k * r^3[/tex]

where T is the period, r is the average distance from the center of the planet or central body, and k is a constant of **proportionality.**

Since we know the period of the moon (tm), we can find the constant of proportionality for the moon's orbit. Assuming the moon's orbit is circular, we have:

[tex]tm^2 = k * rm^3[/tex]

where rm is the average distance from the center of the earth to the moon's center.

Using this relationship, we can find k:

[tex]k = tm^2 / rm^3[/tex]

Next, we can use k to find the period of the satellite, given that the average distance from the center of the earth to the satellite is 1/4 the distance from the center of the earth to the** moon's center**

[tex]rs = rm / 4[/tex]

So the period of the satellite, Ts, is:

[tex]Ts^2 = k * rs^3[/tex]

[tex]Ts^2 = (tm^2 / rm^3) * (rm / 4)^3[/tex]

[tex]Ts = (tm^2 / rm^3)^(1/2) * (rm / 4)^(3/2)[/tex]

So the period of the satellite in terms of the moon's period (tm) is given by the formula:

[tex]Ts = (tm^2 / rm^3)^(1/2) * (rm / 4)^(3/2)[/tex]

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What if an object traveled form position -6m to -1m what is the distance and displacement

### Answers

In unidirectional, the **distance **and **displacement **are the same which is **equal **to 5 meters.

What are displacement and distance?

A **displacement **is a vector in engineering and mechanics that has a length equal to the **shortest route **between a point P's initial and final positions. The displacement is the **vector quantity **that depends on the magnitude as well as **direction**. And follows the law of vector addition.

**Distance **is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. The distance is a **scalar quantity**.

An object traveled from **position **-6m to -1m.

The **distance **will be given as,

Distance = - 1 + 6

Distance = 5 meters

The **displacement **is given as,

Displacement = - 1 + 6

Displacement = 5 meters

The **distance **and **displacement **are the same in the given cases which is 5 meters.

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if i double the length, and halve the diameter of a copper wire, what is the value of its new resistance? original resistance was r0

### Answers

The new **resistance **of the wire will be **4 times** the original resistance (r0).

This is because the resistance of a wire is proportional to its **length **and inversely proportional to its cross-sectional area. Doubling the length of the wire will double its resistance. Halving the diameter of the wire will result in a reduction of its **cross-sectional area** by a factor of 4, which will result in an increase in its resistance by a factor of 4. The net effect is that the resistance of the wire will be 4 times the original resistance.

To be more precise, the resistance R of a wire is given by the equation

R = ρL / A

where ρ is the **resistivity** of the material, L is the length of the wire, and A is its cross-sectional area. So, if we double the length and halve the **diameter**, the new resistance will be given by

R = ρ(2L) / (A/4) = 4ρL / A = 4R0.

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To which regions of the electromagnetic spectrum do the following wavelengths belong :

(a) 250nm

(b) 1500nm

### Answers

(a) A **wavelength** of 250nm corresponds to the ultraviolet (UV) region of the electromagnetic spectrum. This region has shorter wavelengths and higher frequencies than **visible light.**

(b) A wavelength of 1500nm corresponds to the** near-infrared **(NIR) region of the electromagnetic spectrum. This region has longer wavelengths and lower frequencies than visible light and is often used in optical fiber communication and **remote sensing applications.**

Wavelength is a **fundamental concept** in physics that refers to the distance between two successive points on a wave that is in phase. A **wave** is defined as a disturbance that propagates through a medium or space, carrying energy without the transfer of matter. Examples of waves include sound waves, light waves, and** water waves.**

The **wavelength** of a wave is measured as the distance between two consecutive crests or troughs, or any two points that are in phase. It is denoted by the Greek letter lambda (λ) and is usually measured in meters (m) or **nanometers (nm),** depending on the type of wave being studied.

The wavelength of a wave is related to its** frequency** and speed. The frequency of a wave is the number of complete cycles it completes in a unit of time, usually measured in** Hertz (Hz)**. The speed of a wave is the rate at which it travels through a medium or space, usually measured in **meters** per **second** (m/s).

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a transformer is required to give 120 volt from 240 volt mains. if they primary has 5,500 tons how many turn s has the secondary

### Answers

**Answer:**

**Explanation:**

The turns ratio between the primary and secondary of a transformer can be calculated as follows:

Turns ratio = Secondary voltage / Primary voltage

So, in this case:

Turns ratio = 120V / 240V = 1/2

Since the turns ratio is the ratio of the number of turns in the secondary to the number of turns in the primary, the number of turns in the secondary can be found by:

Secondary turns = Primary turns / Turns ratio

In this case, with a primary of 5,500 turns:

Secondary turns = 5,500 turns / (1/2) = 11,000 turns.

So the secondary has 11,000 turns.

2.81 A certain volcano on earth can eject rocks vertically to a maximum height H. (a) How high (in terms of H) would these rocks go if a volcano on Mars ejected them with the same initial velocity? The acceleration due to gravity on Mars is 3.71 m/s², and you can neglect air resistance on both planets. (b) If the rocks are in the air for a time T on earth, for how long (in terms of 7) will they be in the air on Mars?

### Answers

The **height** of a volcano can reach a maximum of 0.3 times that of Earth, and boulders will float in the **air** for 0.38 times as long as they did on Earth.

a) When rocks are ejected from a volcano, their **initial velocity **(V) and the **acceleration due to gravity** (G) dictate how high they may go (g).

The equation for the greatest height (h) is given by h = V2/. (2g). Gravitational acceleration is 9.8 m/s2 on Earth and 3.71 m/s2 on Mars.

With the same beginning velocity as on Earth, boulders blasted from a volcano on Mars would reach a height of h = V2/(2 * 3.71) = (V2/7.42) m.

On Earth, the **maximum height **would be 1/7.32 times 1/2.72 times 0.37 times H.

(b) The **equation **T M = 2V/g may be used to calculate how long the pebbles will remain in the air on Mars (T M).

The equation is T E = 2V/9.8 on Earth and T M = 2V/3.71 on Mars. T M/T E = (2V/3.71) / (2V/9.8) = 3.71/9.8 = 0.38 gives the ratio of the time in the air on Mars to that on Earth.

In other words, the rocks will remain in the air for around 0.38 times as long as they were on earth.

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while the engine is cranked, a voltmeter placed between positive battery post and the positive post of the starter reads less than .01 volt. the cause of this reading could be .

### Answers

A **voltmeter** positioned between the positive thinking requires connection and the positive pin of the starter registers less than.01 volt when the engine is running. This reading's origin could

**What is the purpose of a voltmeter?**

voltmeter: a device for **measuring **voltage. The device used to measure the electric differences between two places in an electrical circuit is called a voltmeter. Digital voltmeters utilize an analog-to-digital converter to display voltage as a **numerical **value; analog voltmeters swing a pointer across a scale in response to the voltage of the circuit.

**What kinds of voltmeters are there?**

Voltmeter classification or types. We offer a **variety **of voltmeter kinds, most of them are based on the construction principle. PMMC Voltmeter (**Permanent **Magnet Moving Coil). Voltmeter for moving iron (MI). Voltmeter of the Electro Dynamometer kind. Voltmeter of the Rectifier Type Voltmeter of the induction kind. Voltmeter of the electrostatic variety.

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a monatomic ideal gas undergoes an isothermal expansion at 300 k, as the volume increased from 0.020 m3 to 0.040 m3. the final pressure is 120 kpa. how much heat energy is transferred to or from the gas? the ideal gas constant is r

### Answers

The **heat energy **is **transferred **to or from the gas is 1.73 Joule. The result is obtained by using the heat energy formula in isothermal process.

What is the heat energy in isothermal process?

In isothermal process, where the temperature is constant, the internal energy also does not change.

ΔU = Q - W = 0

It makes

Q = W

W = nRT ln (V₂/v₁)

Where

Q = heat energy (J)W = work (J)n = number of molesR = ideal gas constant (8.31 JK⁻¹mol⁻¹)T = temperature of the system (K)V₁ & V₂ = Volume of the gas (m³)

We have **a monoatomic** ideal gas undergoes an **isothermal **expansion.

T = 300 KV₁ = 0.020 m³V₂ = 0.040 m³P₂ = 120 kPa

Find the heat energy transferred to or from the gas!

Since it is in isothermal process, the **heat energy transferred** is

Q = W

Q = nRT ln (V₂/v₁)

Q = 1(8,31)(300) ln (0.040/0.020)

Q = 2.493 ln 2

Q = 1.73 Joule

Hence, the **transferred energy **in the **isothermal process **is 1.73 Joule.

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You are running with a carry-on suitcase through the airport. Where should the center-of-mass of the suitcase ideally be located

### Answers

The** center of mass** is usually near the **middle** of the **suitcase** and about halfway up its **height** and at a height that allows you to maintain good **balance** and control while running.

For a carry-on suitcase,. Keeping the center of mass **low** and close to your body can help **reduce** the amount of **effort** required to carry the suitcase, as well as improve **stability** and control while running.

When running with a suitcase, it's important to keep your upper body as **upright** and **relaxed** as possible, while allowing your legs and arms to move freely. This will help you maintain balance and reduce the **strain** on your muscles and joints. Additionally, it's helpful to grip the handle of the suitcase **firmly**, but not too tightly, so that you have control over its movement.

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what is the diffraction limit of a 130-meter radio telescope observing radio waves with a wavelength of 21 centimeters?

### Answers

The **diffraction limit **of the 130-meter radio telescope observing radio waves with a wavelength of 21 centimeters is** 0.0022 meters.**

The diffraction limit of a **radio telescope** is defined as the minimum size of the telescope's aperture that is necessary to produce a diffraction-limited image of an incoming wave. It is given by the formula:

d = 1.22 * λ / D

where d is the diffraction limit, λ is the wavelength of the incoming wave, and D is the diameter of the telescope's aperture.

In this case, the **wavelength **of the incoming **wave **is 21 centimeters, or 0.21 meters, and the diameter of the telescope's aperture is 130 meters. Plugging these values into the formula, we get:

d = 1.22 * 0.21 / 130 = 0.0022 m

So, the diffraction limit of the **130-meter radio telescope **observing** radio waves** with a wavelength of 21 centimeters is** 0.0022 meters.**

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a power station delivers 620 kw of power at 12,000 v to a factory through wires with total resistance 3.0 ohms. how much less power is wasted if the electricity is delivered at 50,000 v rather than 12,000 v?

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A plant receives 620 kw power at 3000 V from a **power** source via lines with a 3.0 total **resistance**.

Describe a power?

The watt W is the SI unit of **power**, and 1 watts equals 1 joule per second (1W=1J/s). Power is the process by which **energy** is used up since power is an **energy** transfer. For instance, a 60-W bulb mieux J of energy every second.

**Power** is a metric for how quickly energy is transformed from one kind to the other. Energy spent over that time can be calculated by integrating, or adding, power over time. Using different units where **power** is stated as a rate may make the relationship between strength and **power** more obvious.

Describe energy?

According to scientists, **energy** is the capacity .

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A 1 kg ball is held motionless above the ground and then released. At impact, it was traveling at 5.50 m/s. How much potential energy did it have before it was released?

Group of answer choices

5 J

12.7 J

15.1 J

9.2 J

### Answers

**Potential **energy of the ball before it was **released **is 15.1 Joule. Hence, **option **(**C**) is correct

What is energy?

**Energy**, which is observable in the execution of labour as well as in the form of heat and light, is the quantitative quality that is transferred to a body or to a physical system in **physics**.

**Energy **is a preserved resource; energy can only be transformed from one form to another and cannot be **created **or destroyed.

From the law of conservation of **energy**:

Potential **energy **before released = kinetic energy during impact

Hence, Potential **energy **before released = 1/2 × 1 × 5.50² Joule

= 15.1 Joule.

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if the object is moving horizontally and at the same constant speed of 0.1 m/s, a force must be exerted on it to maintain that motion. that means someone is doing work! calculate the work required to maintain the motion for 16 seconds.

### Answers

The **work required** to maintain the motion for 16 seconds is 0.16 J.

work = force x distance

In this case, the **distance** is constant and equal to the horizontal distance covered in 16 seconds, which is 0.1 m/s x 16 s = 1.6 m.

The force required to maintain the** horizontal motion **at a constant speed is known as the frictional force, which is equal to the force of friction times the normal **force**. In this case, let's assume the frictional force is 0.1 N.

So the work done in maintaining the horizontal motion for 16 seconds would be:

work = force x distance = 0.1 N x 1.6 m = 0.16 J (joules)

Therefore, the work required to maintain the motion for 16 seconds is 0.16 J.

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calculate the gravitational field strength on the surface of mars. mars has a radius of 3.43x106 m and a mass of 6.37x1023 kg.

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On the surface of Mars, the** gravitational field strength** is roughly [tex]3.71 m/s^2.[/tex]

The influence that a large body has on the space surrounding it, exerting force on another large body, is described by the **gravitational** **field**. The following formula can be used to determine the strength of the gravitational field (g) on the surface of a planet:

g = [tex]\frac {GM}{ r^2}[/tex]

where G is the **gravitational constan**t [tex]6.67 \times 10^{-11} Nm^2/kg^2[/tex], M is the mass of the planet, and r is the radius of the planet.

Plugging in the values for Mars:

g = [tex]6.67 \times 10^{-11} Nm^2/kg^2[/tex] x [tex]\frac{(6.37 \times 10^23 kg)}{(3.43 \times 10^6 m)^2}[/tex]

g= [tex]3.71 m/s^2.[/tex]

Consequently, the **strength** of the **gravitational** **field** on the surface of Mars is about. [tex]3.71 m/s^2.[/tex]

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astronomers split up the ancient constellation of argo navis because it was too large to be useful as a celestial landmark. group of answer choices true false

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**True, **astronomers split up the **ancient constellation of argo navis **because it was too large to be useful as a celestial landmark.

**Why was Argo Navis a constellation but is no longer?**

The only **star** design that was abandoned due to strictly practical considerations is **Argo Navis**; it was simply too large. So Nicolas Louis de Lacaille, a French astronomer, separated it into the constellations **Carina,** Puppis, and Vela in the year 1750.

**Sir John Herschel** suggested the complete dissolution and elimination of **Argo Navis** in 1841 and 1844. Despite this, the constellation and its component pieces continued to be used well into the 20th century. It was given the three-letter abbreviation Arg in 1922, along with the other constellations. In 1930, when the IAU established the 88 contemporary constellations, Carina,** Puppis, and Vela **were split up and demoted to a previous **constellation**.

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